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BBINAPP下载/GMAT/正文

## GMAT数学算术基本概念

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1.平均数(average or arithmetic mean)

BBINAPP下载2.中数(median)

BBINAPP下载To calculate the median of n numbers，first order the numbers from least to greatest;if n is odd，the median is defined as the middle number，while if n is even，the median is defined as the average of the two middle numbers. For the data 6, 4, 7, 10, 4, the numbers, in order, are 4, 4, 6, 7, 10, and the median is 6, the middle number. For the numbers 4, 6, 6, 8, 9, 12, the median is (6+8 )/2 = 7. Note that the mean of these numbers is 7.5.

3.众数(mode)：一组数中的众数是指出现频率最高的数。

4.值域(range)：表明数的分布的量，其被定义为最大值减最小值的差。

5.标准方差(standard deviation)：

One of the most common measures of dispersion is the standard deviation. Generally speaking, the greater the data are spread away from the mean, the greater the standard deviation. The standard deviation of n numbers can be calculated as follows:

BBINAPP下载(1)find the arithmetic mean ;

(2)find the differences between the mean and each of the n numbers ;

BBINAPP下载(3)square each of the differences ;

BBINAPP下载(4)find the average of the squared differences ;

BBINAPP下载(5)take the nonnegative square root of this average.

BBINAPP下载Notice that the standard deviation depends on every data value, although it depends most on values that are farthest from the mean. This is why a distribution with data grouped closely around the mean will have a smaller standard deviation than data spread far from the mean.

6.排列与组合

There are some useful methods for counting objects and sets of objects without actually listing the elements to be counted. The following principle of Multiplication is fundamental to these methods.

BBINAPP下载If a first object may be chosen in m ways and a second object may be chosen in n ways, then there are mn ways of choosing both objects.

BBINAPP下载As an example, suppose the objects are items on a menu. If a meal consists of one entree and one dessert and there are 5 entrees and 3 desserts on the menu, then 5×3 = 15 different meals can be ordered from the menu. As another example, each time a coin is flipped, there are two possible outcomes, heads and tails. If an experiment consists of 8 consecutive coin flips, the experiment has 28 possible outcomes, where each of these outcomes is a list of heads and tails in some order.

BBINAPP下载☆阶乘：factorial notation

☆排列：permutations

The factorial is useful for counting the number of ways that a set of objects can be ordered. If a set of n objects is to be ordered from 1st to nth, there are n choices for the 1st object, n-1 choices for the 2nd object, n-2 choices for the 3rd object, and so on, until there is only 1 choice for the nth object. Thus, by the multiplication principle, the number of ways of ordering the n objects is

n (n-1) (n-2)…( 3) (2) (1) = n!

BBINAPP下载For example, the number of ways of ordering the letters A, B, and C is 3!, or 6：ABC, ACB, BAC, BCA, CAB, and CBA.

BBINAPP下载These orderings are called the permutations of the letters A, B, and C.也可以用P 33表示.

Pkn = n!/ (n-k)!

☆组合：combination

A permutation can be thought of as a selection process in which objects are selected one by one in a certain order. If the order of selection is not relevant and only k objects are to be selected from a larger set of n objects, a different counting method is employed.

Specially consider a set of n objects from which a complete selection of k objects is to be made without regard to order, where 0≤k≤n . Then the number of possible complete selections of k objects is called the number of combinations of n objects taken k at a time and is Ckn.

BBINAPP下载从n个元素中任选k个元素的数目为:

BBINAPP下载Ckn. = n!/ (n-k)! k!

BBINAPP下载例如：从5个不同元素中任选2个的组合为C25 = 5!/2! 3!= 10

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